Invert a binary tree.
4
/ \
2 7
/ \ / \
1 3 6 9
4
/ \
7 2
/ \ / \
9 6 3 1
class Solution {
public:
TreeNode *invertTree(TreeNode *root) {
stack<TreeNode *> st;
st.push(root);
while (!st.empty()) {
auto node = st.top();
st.pop();
if (node) {
swap(node->left, node->right);
st.push(node->left);
st.push(node->right);
}
}
return root;
}
};