# Longest Continuous Increasing Subsequence

## Description

Given an unsorted array of integers, find the length of longest `continuous` increasing subsequence (subarray).

**Example 1:**

```
Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence,
it's not a continuous one where 5 and 7 are separated by 4. 
```

**Example 2:**\


```
Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1. 
```

**Note:** Length of the array will not exceed 10,000.

## Solution

```cpp
class Solution {
public:
    int findLengthOfLCIS(vector<int>& nums) {
        int n = nums.size();
        int len = 0;
        for(int i = 0; i < n; ){
            int j = i + 1;
            while(j < n && nums[j] > nums[j - 1]) ++j;
            if(len < j - i) len = j - i;
            i = j;
        }
        return len;
    }
};
```
